Answer
$y^{29}$
Work Step by Step
Applying the rules of exponents:
$y^8(y^{-7})^{-3}$
$=y^8(y^{(-7)\times(-3)})$
$=y^8y^{21}$
$=y^{29}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Practice and Problem-Solving Exercises - Page 581: 63
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