Answer
$w= \frac{-1}{6}$ or $w=\frac{5}{2}$
Work Step by Step
$12w^2=28w+5$
$12w^2-28w-5=0$
$(2w-5)(6w+1)=0$
$2w-5=0$ or $6w+1=0$
$w= \frac{-1}{6}$ or $w=\frac{5}{2}$
There are two solutions, $w= \frac{-1}{6}$ or $w=\frac{5}{2}$
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