Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 565: 54

Answer

$10.9\;cm$.

Work Step by Step

The given values are: Area $A=120\;cm^2$. Height $=h$ Base $=2h$ Formula for the area of the triangle. $\Rightarrow A=\frac{1}{2}\times Height \times Base$ Substitute all values. $\Rightarrow 120\;cm^2=\frac{1}{2}\times h \times 2h$ Simplify. $\Rightarrow 120\;cm^2=h^2$ Take the square root on both sides. $\Rightarrow \sqrt{120\;cm^2}=\sqrt{h^2}$ Simplify. $\Rightarrow 10.9\;cm=h$.
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