Answer
There are two solutions, $ \pm 2\sqrt 3 \approx 3.5$
Work Step by Step
$-\frac{1}{4}x^2+3=0$
$-\frac{1}{4}x^2=-3$
$x^2=12$
$x=\pm \sqrt 12$
$x=\pm 2\sqrt 3$
There are two solutions, $ \pm 2\sqrt 3 \approx 3.5$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 565: 48
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