Answer
Side length of the largest square is $7.1\;ft$.
Work Step by Step
Let the side of the square be $=a$.
Area of the square $=a^2$.
Given area of the square $=50\;ft^2$.
Equate both areas.
$\Rightarrow a^2=50$
Take the square root on both sides.
$\Rightarrow \sqrt{a^2}=\pm\sqrt{50}$
Simplify.
$\Rightarrow a=\pm7.1\;$
The area cannot have a negative sign.
Hence, the side of the square is $7.1\;ft$.
