Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 564: 16

Answer

There are two solutions for the equation, $\pm 2$

Work Step by Step

$\frac{1}{4}x^2-1=0$ $\frac{1}{4}x^2=1$ $x^2=4$ $x=\pm 2$ There are two solutions for the equation, $\pm 2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.