Answer
See the graph
Work Step by Step
$f(x)=2x^2-6x+1$
Find the axis of symmetry and the coordinates of the vertex.
$x=\frac{-b}{2a}=\frac{-(-6)}{2.2}=\frac{3}{2}$
The axis of symmetry is $x=\frac{3}{2}$. So the x-coordinate of the vertex is $\frac{3}{2}$.
Substitute $\frac{3}{2}$ for x to find the y-coordinate of the vertex.
$y=2(\frac{3}{2})^2-6(\frac{3}{2})+1$
$=\frac{-7}{2}$
The vertex is $(\frac{3}{2},\frac{-7}{2})$
Find some other points for the graph.
$(0,1)$
$(3,1)$
Graph the vertex and the points we found.
