Answer
See the graph
Work Step by Step
$f(x)=3x^2-20x$
Find the axis of symmetry and the coordinates of the vertex.
$x=\frac{-b}{2a}=\frac{-(-20)}{2.3}=\frac{10}{3}$
The axis of symmetry is $\frac{10}{3}$.
So the x-coordinate of the vertex is $\frac{10}{3}$.
Substitute 1 for x to find the y-coordinate of the vertex. $y=3x^2-20x$
$=3(\frac{10}{3})^2-20(\frac{10}{3})$
$=\frac{-100}{3}$
The vertex is $(\frac{10}{3},\frac{-100}{3})$
Graph the vertex and the points we found.
