Answer
$3n^2(2n-1)(n+3)$
Work Step by Step
$6n^4+15n^3-9n^2$
$=3n^2(2n^2)+3n^2(5n)-3n^2(3)$
$=3n^2(2n^2+5n-3)$
$=3n^2(2n^2+6n-n-3)$
$=3n^2[(2n^2-n)+(6n-3)]$
$=3n^2[n(2n-1)+3(2n-1)]$
$=3n^2(2n-1)(n+3)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - Chapter Test - Page 539: 23
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