Answer
$(n-8)^2$
Work Step by Step
$n^2-16n+64$
$=n^2-8n-8n+64$
$=(n^2-8n)-(8n-64)$
$=n(n-8)-8(n-8)$
$=(n-8)^2$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - Chapter Test - Page 539: 18
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