Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 537: 50

Answer

$3(x+3)(x-2)$

Work Step by Step

$3x^{2}+3x-6=$ ...factor out the GCF. $=3(x^{2}+x-6)$ ...find factors of $ac$ with a sum of $b$. ($ac=-6,\ b=1$) $\left[\begin{array}{lll} \text{Factors of -6} & \text{Sum of factors} & \\ 1\text{ and }-6 & -5 & \\ -1\text{ and }6 & 5 & \\ 2\text{ and }-3 & -1 & \\ -2\text{ and }3 & 1 & \text{ is what we need } \end{array}\right]$ ...use the factors you found to rewrite $bx$. $=3(x^{2}-2x+3x-6)$ ...factor by grouping. $=3[x(x-2)+3(x-2)]$ ...factor again. $=3(x+3)(x-2)$
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