Answer
$2(3k-2l)(k-l)$
Work Step by Step
$6k^{2}-10kl+4l^{2}=$
...factor out the GCF.
$=2(3k^{2}-5kl+2l^{2})$
...find factors of $ac$ with a sum of $b$.
($ac=6,\ b=-5$)
$\left[\begin{array}{lll}
\text{Factors of 6} & \text{Sum of factors} & \\
-1\text{ and }-6 & -7 & \\
-2\text{ and }-3 & -5 & \text{ is what we need }
\end{array}\right]$
...use the factors you found to rewrite $bx$.
$=2(3k^{2}-2kl-3kl+2l^{2}$
...factor by grouping.
$=2[k(3k-2l)-l(3k-l)]$
...factor again.
$=2(3k-2l)(k-l)$
