Answer
$-9r^2+11r+3$, Quadratic Trinomial.
Work Step by Step
To put a polynomial into standard form, we apply the commutative property of addition to move around the terms so that their exponents are in descending order. When we do this for $4r+3-9r^2+7r$, we get $-9r^2+4r+7r+3$. We combine like terms to get $-9r^2+11r+3$. To name a polynomial, we must look at the degree and the number of terms. Since this polynomial has $3$ terms with a highest exponent of $2$, we call it a quadratic trinomial.