Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 536: 24

Answer

$9c(5c^{4}-7c^{2}+3)$

Work Step by Step

$45c^{3}=(3\cdot 3)\cdot 5\cdot(c)\cdot c\cdot c\cdot c\cdot c$ $-63c^{3}=-1\cdot(3\cdot 3)\cdot 7\cdot(c)\cdot c\cdot c$ $27c=(3\cdot 3)\cdot 3\cdot(c)$ GCF=$9c$ $45c^{5}-63c^{3}+27c$ $...$factor out the GCF $=9c(5c^{4})+9c(-7c^{2})+9c(3)$ $...$apply the Distributive Property. $=9c(5c^{4}-7c^{2}+3)$
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