Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 527: 34

Answer

$(4x+11)(4x-11)$

Work Step by Step

$16x^{2}-121=$ ...write each term as a square. $=(4x)^{2}-11^{2}$ ...factor using the rule for a difference of two squares. ($a^{2}-b^{2}=(a+b)(a-b),\ a=4x,\ b=11$) $=(4x+11)(4x-11)$
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