Answer
$(4x+11)(4x-11)$
Work Step by Step
$16x^{2}-121=$
...write each term as a square.
$=(4x)^{2}-11^{2}$
...factor using the rule for a difference of two squares.
($a^{2}-b^{2}=(a+b)(a-b),\ a=4x,\ b=11$)
$=(4x+11)(4x-11)$
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