Answer
($p^{3}$-4)($p^{3}$+18)
Work Step by Step
You are given ($p^{63}$$)^{2}$+14$p^{3}$-72.Factor out:
($p^{3}$$)^{2}$+18$p^{3}$-$4p^{3}$-72 -break out the middle number by finding what numbers add up to 14 and multiply to give -72.The numbers are -4 and 18.
(($p^{3}$$)^{2}$+18$p^{3}$)-($4p^{3}$-72) -find the GCD of the first two and last two terms-
$p^{3}$($p^{3}$+18)-4($p^{3}$+18) -take ($p^{3}$+18) and factor it out-
The factored expression is ($p^{3}$-4)($p^{3}$+18)
