Answer
(h+15j)(h-6j)
Work Step by Step
You are given $h^{2}$+9hj-90$j^{2}$. Factor it out:
$h^{2}$+15hj-6hj$j^{2}$ -break out the middle value-
($h^{2}$+15hj)+(-6hj-90$j^{2}$) -group the first two and last two terms-
h(h+15j)-6j(h+15j) -Find the GCF of each grouping-
(h+15j)(h-6j) -factor out the common term-
=(h+15j)(h-6j)
