Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-5 Factoring x2+bx+c - Practice and Problem-Solving Exercises - Page 515: 12

Answer

$(t-4)(t-6)$

Work Step by Step

$-10$ is negative, so we list negative factors of $24$. $\left[\begin{array}{llll} \text{ Factors of 24 } & \text{Sum of factors}-1 \text{ and }-24 & -25 & \\ -2\text{ and }-12 & -14 & \\ -3\text{ and }-8 & -11 & \\ -4\text{ and }-6 & -10 & \text{...is what we need} \end{array}\right]$ $t^{2}-10t+24=(t-4)(t-6)$
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