Answer
$\frac{1}{a}$
Work Step by Step
You are given $a^{2}$$b^{0}$($a^{-3}$).
$a^{2}$$a^{-3}$ -any number raised to 0 equals 1 so $b^{0}$=1-
$a^{2+-3}$ -add the exponents since they have the same base-
$a^{-1}$ -use the exponent rule $x^{-y}$=$\frac{1}{x^y}$-
The simplified expression is $\frac{1}{a}$
