Answer
$\frac{27t^{\frac{1}{2}}}{8}$
Work Step by Step
We are given
$(3t^{\frac{1}{6}})^3(2t^0)^{-3}$
$=3^3t^{\frac{1}{2}}2^{-3}$
$=\frac{27t^{\frac{1}{2}}}{8}$
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