Answer
$x^{2}$$y^{3}$
Work Step by Step
You have $\sqrt[3] x^6y^9$.Simplify the expression:
$\sqrt[3] x^6$ $\sqrt[3] y^9$ -apply the radical rule that $\sqrt[n] ab$=$\sqrt[n] a$ $\sqrt[n] b$-
$x^{6/3}$ $x^{9/3}$ -apply radical rule: $\sqrt[n] a^m$=$a^{m/n}$-
=$x^{2}$$y{3}$
