Answer
$\frac{e^2{^0}}{81c^1{^2}}$
Work Step by Step
You have the expression ($\frac{3c^3}{e^5}$$)^{-4}$.Simplify the expression:
($\frac{e^5}{3c^3}$$)^{4}$ -flip the numerator and the denominator because $a^{-b}$=$\frac{1}{a^b}$-
($\frac{e^5{^*4}}{3c^3*4}$) -raise the numerator and denominator to power-
=$\frac{e^2{^0}}{81c^1{^2}}$
