Answer
$-\frac{4}{3r^{10}z^8}$
Work Step by Step
$(-2r^{-4})^2(-3r^2z^8)^{-1}$
$=(-2)^2r^{-8}(-3)^{-1}r^{-2}z^{-8}$
$=-\frac{4}{3}r^{-10}z^{-8}$
$=-\frac{4}{3r^{10}z^8}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 476: 39
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