Answer
$7\sqrt{2d}$
Work Step by Step
Apply $\ \ \sqrt[n]{a^{m}}=a^{m/n},$
$(98d)^{1/2}=\sqrt[2]{(98d)^{1}}=\sqrt{49\cdot 2d}$
$=\sqrt{7^{2}\cdot 2d}$
=$7\sqrt{2d}$
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