Answer
The answer is -12$x^{6}$ + 40$x^{4}$
Work Step by Step
To solve this
= -4$x^{3}$($3x^{3}$ - 10x)
=( -4$\times$3)($x^{3}$$\times$$x^{3}$)+(-4$\times$-10)($x^{3}$$\times$x)
= -12($x^{3+3})$+(40)($x^{3+1})$
= -12$x^{6}$ + 40$x^{4}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 430: 45
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