Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-4 Applications of Linear Systems - Practice and Problem-Solving Exercises - Page 392: 33

Answer

$x = -2$ $y = -2$

Work Step by Step

$2x + 4y = -12$ $-6x + 5y = 2$ To use elimination, we need to make one of the variables the same in each equation: $6x + 12y = -36$ $-6x + 5y = 2$ Add the two equations together: $17y = -34$ Divide each side by $17$ to solve for $y$: $y = -2$ Now that we have the value for $y$, we can plug it into one of the equations to solve for $x$: $2x + 4(-2) = -12$ Multiply first: $2x - 8 = -12$ Add $8$ to each side of the equation: $2x = -4$ Divide each side of the equation by $2$: $x = -2$
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