Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-4 Applications of Linear Systems - Practice and Problem-Solving Exercises - Page 392: 32

Answer

$x = -7$ $y = 6$

Work Step by Step

$x + 3y = 11$ $2x + 3y = 4$ To use elimination, we need to make one of the variables the same in each equation. We see that we have this with the y terms: $-x - 3y = -11$ $2x + 3y = 4$ Add the two equations together: $x = -7$ Now that we have the value for $x$, we can plug it into one of the equations to solve for $y$: $-7 + 3y = 11$ Add $7$ to each side of the equation: $3y = 18$ Divide each side of the equation by $3$: $y = 6$
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