Answer
The range is {-7, -2, -1, 3}
Work Step by Step
f(x) = 8x - 3
The domain is {-$\frac{1}{2}$,$\frac{1}{4}$,$\frac{3}{4}$,$\frac{1}{8}$}.
The domain gives the x value so we substitute the x into the equation f(x) = 8x - 3. Thus;
x= -$\frac{1}{2}$
f(-$\frac{1}{2}$) = 8(-$\frac{1}{2}$) - 3
f(-$\frac{1}{2}$) = -7
x= $\frac{1}{4}$
f($\frac{1}{4}$) = 8($\frac{1}{4}$) - 3
f($\frac{1}{4}$) = -1
x= $\frac{3}{4}$
f($\frac{3}{4}$) = 8($\frac{3}{4}$) - 3
f($\frac{3}{4}$) = 3
x= $\frac{1}{8}$
f($\frac{1}{8}$) = 8($\frac{1}{8}$) - 3
f($\frac{1}{8}$) = -2
Therefore we get the range to be {-7, -2, -1, 3}.
