Answer
Therefore we get the range to be {0, 0.04 , 1.44 , 16}
Work Step by Step
h(x) = x2
The domain is {-1.2,0,0.2,1.2,4}.
The domain gives the x value so we substitute the x into the equation h(x) = x2
x=-1.2
$h(-1.2) = (−1.2)^2$
h(-1.2) = 1.44
x=0
$h(0) = (0)^2$
h(0) = 0
x=0.2
$h(0.2) = (0.2)^2$
h(0.2) = 0.04
x=1.2
$h(1.2) = (1.2)^2$
h(1.2) = 1.44
x=4
$h(4) = (4)^2$
h(4) = 16
Therefore we get the range to be {0, 0.04 , 1.44 , 16}
