Answer
$C'=\{ 2, 6, 10, 14\}$
Work Step by Step
We have $U=\{ 2, 4,6,8,10,12,14,16\}$
and $C=\{ 4,8,12,16 \}$
The complement of set C is the set of all elements in the universal set that are not in the set.
So $C'=\{ 2, 6, 10, 14\}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 3 - Solving Inequalities - 3-5 Working With Sets - Practice and Problem-Solving Exercises - Page 198: 46
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