Answer
{$x|x\lt0$}
Work Step by Step
$=2(3x+7)\gt-14$
$-6x-14\gt-14$
$-6x-14+14\gt-14+14$
$-6x\gt0$
$\frac{-6x}{-6}\gt\frac{0}{-6}$
$x\lt0$
{$x|x\lt0$}
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 3 - Solving Inequalities - 3-5 Working With Sets - Practice and Problem-Solving Exercises - Page 198: 40
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