Answer
4a. 21%
4b. 21%
4c. 21%
Work Step by Step
4a.
$A=(4)(4)=16$
$4\times10%=4$$\times0.1=0.4$
Add 0.4 to the already given length to the new length of 4.4
$A=(4.4)(4.4)=19.36$ This is the new area
p%=$\frac{19.36-16}{16}$
$=\frac{3.36}{16}$
$0.21$ or 21%
4b.
$A=(6)(6)=36$
$6\times10%$$=6\times0.1=0.6$
Add 0.6 to the old length to get the new length
$6+0.6=6.6$
$A=(6.6)(6.6)=43.56$ This is the new area of the square
percent increase
new amount-original amount/original amount
p%=$\frac{43.56-36}{36}$
$=\frac{7.56}{36}$
$0.21$ or $21$%
4c.
21%
The new length of 10 is 1.1 times as great as the original length
$10\times10$%=0.1
$10+0.1=10.1$
$\frac{10.1}{10}=1.1$
$1.1^2=1.21$ or 121%
This is a 21% increase over the original amount of 100%
