Answer
about 51.26%
Work Step by Step
$V=\pi r^{2}h$- formula for the volume of a cylinder
$0.5$ This is the accurate possible error to the nearest foot
The measured volume
$V=(3.14)(2.5)^2(2)$
$v=39.25$
The minimum volume the diameter is 5ft so the possible minimum error is 4.5ft (5ft-0.5ft). The radius is half of the diameter: $4.5\div2=2.25$
$V=(3.14)(2.25)^2(1.5)$
$V=23.84$
The maximum volume
The maximum volume the diameter is 5ft so the possible minimum error is 5.5ft (5ft+0.5ft). The radius is half of the diameter: $5.5\div2=2.75$
$V=3.14(2.75)^2(2.5)$
$59.37$
Difference in volume
$|23.84-39.25|$
$15.41$
Difference in volume
$|59.37-39.25|$
$20.12$
Greatest possible percent error=greatest difference in volume/measured volume
$\frac{20.12}{39.25}\approx0.5126$ or $51.26$%
