Answer
$x=4$ or $x=-1$
Work Step by Step
Given:
$y=x^2-x-6$
$y=2x-2$
Substitute:
$x^2-x-6=2x-2$
$x^2-3x-4=0$
$(x-4)(x+1)=0$
$x-4=0$ or $x+1=0$
$x=4$ or $x=-1$
The solutions of the system are $x=4$ and $x=-1$.
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