Answer
The negative solution of the equation is $x=-\frac{3}{2}$.
Work Step by Step
Given: $2x^2+x=3$
$2x^2+x-3=0$
$(x-1)(2x+3)=0$
$x=1$ or $x=-\frac{3}{2}$
The negative solution of the equation is $x=-\frac{3}{2}$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Common Core Cumulative Standards Review - Selected Response - Page 722: 17
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