Answer
Simplified expression: $\frac{x+3}{5}$
Excluded value: $-3$
Work Step by Step
$\frac{x^2+6x+9}{5x+15}$
In a rational expression, a value would be excluded if it makes a denominator of any fraction equal to zero. In this case, all solutions of $5x+15=0$ would be excluded values.
$5x+15=0$
$5x=-15$
$x=-3$
Then, we can simplify the expression.
$\frac{x^2+6x+9}{5x+15}$
$=\frac{(x+3)^2}{5(x+3)}$
$=\frac{x+3}{5}$
