Answer
The vertical asymptotes are the lines $x=2$ or $x=0$
The horizontal asymptote is the line $y=0$
Work Step by Step
Given $g(x)=\frac{1}{x^2-2x}$
$x^2-2x=0 $
$x=2$ or $x=0$
The vertical asymptotes are the lines $x=2$ or $x=0$.
The horizontal asymptote is the line $y=0$.
Make a list of values:
$x=−2→ y=\frac{1}{8}$
$x=−1→ y=\frac{1}{3}$
$x=0→ y=0$
$x=1→ y=\frac{1}{3}$
$x=2→ y=\frac{1}{8}$