Answer
The vertical asymptote is the line $x=1$.
The horizontal asymptote is the line $y=0$.
Work Step by Step
Given $g(x)=\frac{1}{(x-1)^2}$
$x-1=0 $
$x=1$
The vertical asymptote is the line $x=1$.
The horizontal asymptote is the line $y=0$.
Make a list of values:
$x=−2→ y=\frac{1}{9}$
$x=−1→ y=\frac{1}{4}$
$x=0→ y=1$
$x=1→ y=0$
$x=2→ y=1$
