Answer
$=\frac{-4k-61}{(k-4)(k+10)}$
Work Step by Step
$\frac{k-11}{k^2+6k-40}-\frac{5}{k-4}$
$=\frac{k-11}{(k-4)(k+10)}-\frac{5}{k-4}$
$=\frac{(k-11)-5(k+10)}{(k-4)(k+10)}$
$=\frac{-4k-61}{(k-4)(k+10)}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 697: 58
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