Answer
$=\frac{3h^2+2ht+4h}{2t^2-8}$
Work Step by Step
$\frac{3h^2}{2t^2-8}+\frac{h}{t-2}$
$=\frac{3h^2+h(2t+4)}{2t^2-8}$
$=\frac{3h^2+2ht+4h}{2t^2-8}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 697: 57
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