Answer
$2$
Work Step by Step
Given : $\frac{3n+2}{n+4} - \frac{n-6}{n+4}$
$= \frac{3n+2-(n-6)}{n+4}$
(Since they have the same denominator)
$= \frac{3n-n+2+6}{n+4}$
$= \frac{2n+8}{n+4}= \frac{2\times(n+4)}{n+4}$
$= 2$
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