Answer
$\frac{1}{n+2}$
Work Step by Step
Given : $\frac{n}{n^{2}+4n+4} + \frac{2}{n^{2}+4n+4}$
This becomes : $\frac{n+2}{n^{2}+4n+4}$
$=\frac{n+2}{(n+2)(n+2)}$
$=\frac{1}{n+2}$
(After dividing out the common factor (n+2))
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