Answer
The answer is $b+6+\frac{25}{2b+4}$.
Work Step by Step
$(49+16b+2b^2) \div (2b+4)$
$=(2b^2+16b+49) \div (2b+4)$
$b+6$
_________________________
$2b+4)2b^2+16b+49$
$-2b^2-4b$
_________________________
$12b+49$
$-12b-24$
_________________________
$25$
The answer is $b+6+\frac{25}{2b+4}$.
