Answer
$3\sqrt 2-4\sqrt 3$
Work Step by Step
Applying the rules of radicals:
$\sqrt 3(\sqrt 6-4)$
$=\sqrt 3.\sqrt 3.2-4\sqrt 3$
$=3\sqrt 2-4\sqrt 3$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 10 - Radical Expressions and Equations - Mid-Chapter Quiz - Page 632: 25
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