Answer
$x\sqrt 6$
Work Step by Step
Applying the rules of radicals:
$\frac{-3\sqrt 14x^3}{-\sqrt 21x}$
$=\frac{3\sqrt 2.7.x^3}{\sqrt 3.7.x}$
$=\frac{3x\sqrt 2}{\sqrt 3}$
$=x\sqrt 6$
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