Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 656: 59

Answer

$BC=5.2$. $AC=24.5$.

Work Step by Step

The given values are $AB=25$ and $\angle A=12^{\circ}$. The triangle is shown in the image file. Use trigonometric ratios. $\Rightarrow \sin A =\frac{BC}{AB}$ Multiply both sides by $AB$. $\Rightarrow AB\cdot \sin A =AB\cdot\frac{BC}{AB}$ Simplify. $\Rightarrow AB\cdot \sin A =BC$ Substitute all values. $\Rightarrow 25\cdot \sin (12^{\circ}) =BC$ Simplify. $\Rightarrow 5.2=BC$. Now use $\Rightarrow \cos A =\frac{AC}{AB}$ Multiply both sides by $AB$. $\Rightarrow AB\cdot \cos A =AB\cdot\frac{AC}{AB}$ Simplify. $\Rightarrow AB\cdot \cos A =AC$ Substitute all values. $\Rightarrow 25\cdot \cos (12^{\circ}) =AC$ Simplify. $\Rightarrow 24.5=AC$.
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