Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 656: 57

Answer

$AB=10.2$. $BC=6.3$.

Work Step by Step

The given values are $AC=8$ and $\angle B=52^{\circ}$. The triangle is shown in the image file. Use trigonometric ratios. $\Rightarrow \sin B =\frac{AC}{AB}$ Multiply both sides by $\frac{AB}{\sin B}$. $\Rightarrow \frac{AB}{\sin B}\cdot \sin B =\frac{AB}{\sin B}\cdot\frac{AC}{AB}$ Simplify. $\Rightarrow AB=\frac{AC}{\sin B}$ Substitute all values. $\Rightarrow AB=\frac{8}{\sin 52^{\circ}}$ Simplify. $AB=10.2$. Now use $\Rightarrow \tan B =\frac{AC}{BC}$ Multiply both sides by $\frac{BC}{\tan B}$. $\Rightarrow \frac{BC}{\tan B} \cdot \tan B =\frac{BC}{\tan B} \cdot \frac{AC}{BC}$ Simplify. $\Rightarrow BC =\frac{AC}{\tan B}$ Substitute all values. $\Rightarrow BC =\frac{8}{\tan 52^{\circ}}$ Simplify. $BC=6.3$.
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