Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 638: 62

$m=\frac{-2}{3}$ or $m=\frac{-3}{2}$

We are given: $6m^2+13m+6=0$ $m=\frac{-13\pm \sqrt (13)^2-4.6.6}{2.6}$ $m=\frac{-13 \pm 5}{12}$ $m=\frac{-13 + 5}{12}$ or $m=\frac{-13 - 5}{12}$ $m=\frac{-2}{3}$ or $m=\frac{-3}{2}$ There are two solutions: $m=\frac{-2}{3}$ or $m=\frac{-3}{2}$.