Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 638: 59

Answer

$-\frac{2\sqrt 3-2\sqrt 8}{5}$

Work Step by Step

We are given: $\frac{2}{\sqrt 3+\sqrt 8}$ Multiply each side with $\frac{\sqrt 3-\sqrt 8}{\sqrt 3-\sqrt 8}$ $=\frac{2(\sqrt 3-\sqrt 8)}{3-8}$ $=-\frac{2\sqrt 3-2\sqrt 8}{5}$
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