Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Lesson Check - Page 636: 2

3

You are given $\sqrt (r+5)$=2$\sqrt (r-1)$.Solve for R: $\sqrt (r+5)$=2$\sqrt (r-1)$ -square both sides- r+5=4r-4 r+9=4r 9=3r 3=r Verify the solution by substituting r=3 into the equations.R=3 is true so 3 is the solution.